Alok is attending a workshop "How to do more with less" and today's theme is Working with fewer digits . The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as well as womankind) had only worked with fewer digits.
The problem posed at the end of the workshop is
How many 5 digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?
Can you help Alok find the answer?
625
375
3125
500
Solution:Alok is attending a workshop "How to do more with less" and today's theme is Working with fewer digits . The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as well as womankind) had only worked with fewer digits.
The problem posed at the end of the workshop is
How many 5 digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?
Can you help Alok find the answer?
625
375
3125
500
a no divisible by 4 means it contain ending two digits as 12,24,32,44,52
ReplyDelete_ _ _ 1 2 have 125 posiblities 5*5*5
so total 625 possibilities
ya ryt!!
ReplyDeletebut it will contain numbers without repetition also...
ReplyDeleteSid is a donkey!
ReplyDeletecan any one give me crt explanation
ReplyDeleteit 375...
ReplyDeleteas numbers that are divisible by 4 ends with 12 or 24 or 32.
and the first three digits of the number can be either of 1,2,3,4,5
so the total digits possible are 5*5*5*(3) as 3 sets are possible = 375
(soory i forgot the case of 44 n 52 )so answer is it 625...
ReplyDeleteas numbers that are divisible by 4 ends with 12 or 24 or 32 0r 44 or 52.
and the first three digits of the number can be either of 1,2,3,4,5
so the total digits possible are 5*5*5*(5) as 5 sets are possible = 625
guys you are actually missing out the pont that we have taken two digits together so 5* 5*5 is enough
ReplyDelete